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Free Online Mock Chemistry Multiple Choice Test on Chemical Kinetics

Sub Category : Chemical Kinetics Test : 11 Time Left :
1) For a reaction A+2B->C+D,the following data were obtained
Expt. Initial concentration			Initial Rate of formation of D
(moles litre-1)					(moles litre-1 min-1)
									  
	[A]		[B]	
1.	0.1		0.1		6.0 Ã- 10-3
2.	0.3		0.2		7.2 Ã- 10-2
3.	0.3		0.4		2.88 Ã- 10-1
4.	0.4		0.1		2.4 Ã- 10-2
The correct rate law expression will be
(1) Rate = k[A] [B]  (2) Rate = k[A] [B]2  (3) Rate = k[A]2 [B]2  (4) Rate = k[A]2 [B].
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2) 
For the reaction, 2A+B->Products, the following initial rates were obtained at various initial concentrations:
[A]		[B]		Rate(mol l-1 sec-1)
0.1 M	0.2 M	0.46
0.2 M	0.2 M	1.84
0.2 M	0.1 M	0.92
The rate law for the reaction is
(1) Rate = k[A]2 [B]0  (2) Rate = k[A] [B]  (3) Rate = k[A]2 [B]  (4) Rate = k[A] [B]2
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3) For the reaction, the specific rate constant is (1) 23 sec-1 (2) 0.46 l mol-1 sec-1 (3) 2.3 Ã- 102 l2 mol-2 sec-1 (4) 1.125 Ã- 102 l2 mol-2 sec-1.
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4) Given the following data for the reaction:X+Y->Z
[X]		[Y]		Rate Ã- 10-1 ms-1
1.0 M	1.0 M	0.25
2.0 M	1.0 M	0.50
1.0 M	2.0 M	0.25
1.0 M	3.0 M	0.25
Which one is the rate law equation?
(1) Rate = k [X]  [Y]  (2) Rate = k [X]0  [Y]1  (3) Rate = k [X]  [Y]0  (4) Rate = k [X]  [Y]2.
1 2 3 4
 
5) For decomposition of N2O5(g) dissolved in CCl4 2N2O5(g)->4NO2(g) + O2(g),The following data at 300 K is given:
Concentration of	Rate of
Reactant			decomposition
0.170 M				0.050 M hr-1
0.340 M				0.100 M ht-1
0.680 M				0.200 M hr-1
The rate equation for the reaction is
(1) rate = k[N2O5]2 (2) rate = k[N2O5] (3) rate = k[N2O5]3 (4) rate= k[N2O5]0.
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